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標題:

could you help me about A math

發問:

1) find the remainder x^3 +2x-5 is divided by x+3 2) 5x^3+4x^2-6x+7 is divided by x-2 3) find the value of K if (3x+K)^3 + (4x-7)^2 has a remainder of 33 when divided by x-3 4) x+2 is a factor of (x+1)^5 +(5x+K)^3

最佳解答:

1) find the remainder x^3 +2x-5 is divided by x+3 Remainder theorem Remainder= (-3)^3 + 2(-3) - 5 = -27 - 6 - 5 = -38 2)5x^3+4x^2-6x+7 is divided by x-2 Remainder theorem Remainder = 5(2)^3 + 4(2)^2 -6(2) + 7 = 40 + 16 - 12 + 7 = 51 3) find the value of K if (3x+K)^3 + (4x-7)^2 has a remainder of 33 when divided by x-3 Remainder theorem 33 = [3(3)+K]^3+(4*3 - 7)^2 33 = (9+K)^3 + 25 8 = (9+K)^3 2 = 9+K K = -7 4)x+2 is a factor of (x+1)^5 +(5x+K)^3 Factor theorem 0 = (-2+1)^5 + (-10+K)^3 0 = -1 + (-10+K)^3 1 = K-10 K = 11

其他解答:6CC7293C789E3310