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標題:

Math題數題

發問:

1) the 1 st term and 2nd term and 2 and 3 respectively . For any positive integer n , the (n+2)th term is the product of the n th term and the (n+1) th term . find the 7th term of the sequence2) If 4x-5y=0 ,find (3a-b) : (b+2c)3) If 2x=3y=4z ,find (x-y+z) : (z+y-z) 4) If a pair of trousers is sold... 顯示更多 1) the 1 st term and 2nd term and 2 and 3 respectively . For any positive integer n , the (n+2)th term is the product of the n th term and the (n+1) th term . find the 7th term of the sequence 2) If 4x-5y=0 ,find (3a-b) : (b+2c) 3) If 2x=3y=4z ,find (x-y+z) : (z+y-z) 4) If a pair of trousers is sold at $228 ,the percentage profit will be 90% .What should be the selling price of the trousers in order to gain a profit of 140% ? 5) A shopkeeper sells two cameras for $5400 each .He losee 10% on one of them and gains 20% on the other .Find the overall percentage profit or percentage loss that shopkeeper can make ,correct to the nearest 0.01%

最佳解答:

1) T(3) = 2 x 3 = 6 T(4) = 3 x 6 = 18 T(5) = 6 x 18 = 108 T(6) = 18 x 108 = 1944 T(7) = 108 x 1944 = 209952 2) 4x - 5y = 0 4x = 5y x/y = 5/4 x : y = 5 : 4 Let x = 5k and y = 4k ( 3a - b) : (b + 2c ) = [3(5k) - (4k)] : [(5k) + 2(4k)] = 11 : 18 3) 2x = 3y = 4z 2x/12 = 3y/12 = 4z/12 x/6 = y/4 : z/3 x : y : z = 6 : 4 : 3 (x - y + z) : (z + y - z) = (6 - 4 + 3) : (3 + 4 - 3) = 5 : 4 I think it should be (x - y + z) : (z + y - x). If so, (x - y + z) : (z + y - x) = (6 - 4 + 3) : (3 + 4 - 6) = 5 : 1 4) Cost of the pair of trousers = $228 ÷ (1 + 90%) = $120 Selling price in order to gain a profit of 140% = $120 x (1 + 140%) = $288 5) Total cost of the two cameras = $5400 ÷ (1 - 10%) + $5400 ÷ (1 + 20%) = $6000 + $4500 = $10500 Total selling price of the two cameras = $5400 x 2 = $10800 Selling price > Cost. Profit is made. Profit percentage = [(10800 - 10500)/10500] x 100% = 2.86%

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